Subject: 3 Ways to input filter in JDNI for special characters
Author: JNDI
In response to: Special Characters in Filter -- RFC-2254
Posted on: 03/08/2010 08:17:11 PM
The following is a sample of JNDI doing filter search.
public static void main(String[] args)
{
Hashtable env = new Hashtable(11);
env.put(Context.INITIAL_CONTEXT_FACTORY,
"com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, "ldap://myServer.mycompany.com:389");
env.put(Context.SECURITY_AUTHENTICATION, "simple");
env.put(Context.SECURITY_PRINCIPAL, "user");
env.put(Context.SECURITY_CREDENTIALS, "password");
DirContext ctx = null;
try {
ctx = new InitialDirContext(env);
SearchControls ctls = new SearchControls();
String base_dn = "dc=example,dc=com";
String filter = "(objectclass=*)";
NamingEnumeration enu = ctx.search(base_dn,filter,ctls);
while(enu.hasMore()){
SearchResult sr = (SearchResult)enu.next();
System.out.println("rdn='" +sr.getName()+"'");
}
}catch(NamingException e){
e.printStackTrace();
}finally{
try{
ctx.close();
}catch(Exception e){
}
}
}
For an user in directory server with surename (sn) being 'Leé', the actual format in the storage is:
The exactly matching filter to bring out the user can be written in three different ways:
1) Simlply type in the special character if your keyboard allows:
String filter = "(sn=Leé)";
2) Type in the unicode of the special character:
String filter = "(sn=Le\u00E9)";
3) Type in the UTF-8 string representation of the escaped special character as in the RFC 2254:
String filter = "(sn=Le\C3\A9)";
>
> On 08/17/2006 02:07:07 PM SteveHB wrote:
(sn=Lu\c4\8di\c4\87)
This example illustrates the use of the escaping mechanism to represent various non-ASCII UTF-8 characters.
References:
